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The escape velocity on the surface of the earth is 11.2 `kms^(-1)`. If mass and radius of a planet is 4 and 2 tims respectively than that of the earth, what is the escape velocity from the planet?A. 11.2 km/sB. 1.112 km/sC. 15.8 km/sD. 22.4 km/s |
Answer» Correct Answer - c `v_(e)=sqrt(2gR)=sqrt((2GM)/(R))=sqrt((2xxGxx4M)/(2R))` `=sqrt2sqrt((2GM)/(R))=sqrt2=11.2=15.8km//s` |
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