1.

The expanded form of log \(\cfrac{343}{125}\) is ………………… A) 7 (log 5 – log 7) B) 4 (log 5 – log7) C) 2 (log 7 – log 5)D) 3 (log 7 – log 5)

Answer»

Correct option is (D) 3 (log 7 – log 5)

\(log\,\frac{343}{125}=log\,\frac{7^3}{5^3}\)

\(=log\,(\frac75)^3=3\,log\,\frac75\)

= 3 (log 7 – log 5)

Correct option is D) 3 (log 7 – log 5)



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