InterviewSolution
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InterviewSolution
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The experiment data for the reaction `2A + B_(2) rarr 2AB` is `|{:("Experiment",[A] M,[B_(2)] M,"Initial rate" (mol L^(-1) s^(-1)),),(I,0.50,0.5,1.6 xx 10^(-4),),(II,0.50,1.0,3.2 xx 10^(-4),),(III,1.00,1.0,3.2 xx 10^(-4),):}|` Write the most probable rate equation for the reacting giving reason for you answer. |
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Answer» Let rate expression be: rate `=K[A]^(m)[B_(2)]^(n)` Thus, `1.6xx10^(-4)=K(0.5)^(m)(0.5)^(n) …(i)` `3.2xx10^(-4)=K(0.5)^(m)(1.0)^(n) …(ii)` `3.2xx10^(-4)=K(1.0)^(m)(1.0)^(n) …(iii)` By eqs. (i) and (ii), `n=1` By eqs. (ii) and (iii), `m=0` Rate`=(dx)/(dt)K[B_(2)]^(1)` |
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