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The expression `(1+sin22^@sin33^@sin35^@)/(cos^2 22^@+cos^2 33^@+cos^2 35^@)` simplifies to |
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Answer» Correct Answer - 0.5 Let `(A)/(2) = 22^(@), (B)/(2) = 33^(@), (C )/(2) = 35^(@)` `rArr A +B+C= 180^(@)` In `DeltaABC, cos^(2) ""(A)/(2) + cos^(2)""(B)/(2) +cos^(2) ""(C )/(2)` `= 2+ 2 sin ""(A)/(2)* sin""(B)/(2)* sin ""(C )/(2)` Hence, `(1+ sin 22^(@) sin 33^(@) sin 35^(@))/(cos ^(2) 22^(@) + cos ^(2) 33^(@) + cos ^(2) 35^(@)) = (1)/(2)` |
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