1.

The expression for the capacity of the capacitor formed by compound dielectric placed between the plates of a parallel plate capacitor as shown in figure, will be (area of plate = A)

Answer»

`(epsi_(0)A)/(((d_(1))/(K_(1)) + (d_(2))/(K_(2)) + (d_(3))/(K_(3))))`
`(epsi_(0A))/(((d_(1) + d_(2) + d_(3))/(K_(1) + K_(2) + K_(3))))`
`(epsi_(0)A(K_(1) K_(2) K_(3)))/(d_(1) d_(2) d_(3))`
`epsi_(0) ((AK_(1))/(d_(1)) + (AK_(2))/(d_(2)) + (AK_(3))/(d_(3)))`

Answer :A


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