. The exterior angles of a pentagon are 2x°,(2x+5)°,(3x+10)°,(3x-15

1.	. The exterior angles of a pentagon are 2x°,(2x+5)°,(3x+10)°,(3x-15)°, and (x+30 )°a. Find the value of xb. Find the smallest interior angle of the pentagonc. Find the largest interior angle of the pentagon
Answer» Step-by-step explanation: sum of ANGLES is360 then 2x+5+3x+10+3x-15+2x+X+30 =360 15 -15 GET cancel 11x=330 x=30 weget XAS 30 then the smallest angle is 2x; X+30 =60 and largest angle is 3x+10 = 100 this is the ANSWER for above question

. The exterior angles of a pentagon are 2x°,(2x+5)°,(3x+10)°,(3x-15)°, and (x+30 )°a. Find the value of xb. Find the smallest interior angle of the pentagonc. Find the largest interior angle of the pentagon

Answer»

Step-by-step explanation:

sum of ANGLES is360

then 2x+5+3x+10+3x-15+2x+X+30 =360

15 -15 GET cancel

11x=330

x=30

weget XAS 30

then the smallest angle is 2x; X+30 =60

and largest angle is 3x+10 = 100

this is the ANSWER for above question