The fat C57H104O6 (s) is metabolized via the following reaction. ca

1.	The fat C57H104O6 (s) is metabolized via the following reaction. calculate the energy (KJ) liberated when 1g of this fat reacts. C57H104O6(s)+80O2(g)→57CO2(g)+52H2O(l) Given the enthalpies of formation: ΔH0f(C57H104O6,s)=−70870 kJ/mol ΔH0f(H2O,l)=−285.8 kJ/mol ΔH0f(CO2,g)=−393.5 kJ/mol
Answer» The fat $C_{57} H_{104} O_{6}$ (s) is metabolized via the following reaction. calculate the energy (KJ) liberated when 1g of this fat reacts. $C_{57} H_{104} O_{6} (s) + 80 O_{2} (g) \to 57 C O_{2} (g) + 52 H_{2} O (l)$ Given the enthalpies of formation: $Δ H_{f}^{0} (C_{57} H_{104} O_{6}, s) = - 70870$ kJ/mol $Δ H_{f}^{0} (H_{2} O, l) = - 285.8$ kJ/mol $Δ H_{f}^{0} (C O_{2}, g) = - 393.5$ kJ/mol

The fat C57H104O6 (s) is metabolized via the following reaction. calculate the energy (KJ) liberated when 1g of this fat reacts. C57H104O6(s)+80O2(g)→57CO2(g)+52H2O(l) Given the enthalpies of formation: ΔH0f(C57H104O6,s)=−70870 kJ/mol ΔH0f(H2O,l)=−285.8 kJ/mol ΔH0f(CO2,g)=−393.5 kJ/mol

Answer»

The fat $C_{57} H_{104} O_{6}$ (s) is metabolized via the following reaction.
calculate the energy (KJ) liberated when 1g of this fat reacts.

$C_{57} H_{104} O_{6} (s) + 80 O_{2} (g) \to 57 C O_{2} (g) + 52 H_{2} O (l)$

Given the enthalpies of formation:

$Δ H_{f}^{0} (C_{57} H_{104} O_{6}, s) = - 70870$ kJ/mol
$Δ H_{f}^{0} (H_{2} O, l) = - 285.8$ kJ/mol
$Δ H_{f}^{0} (C O_{2}, g) = - 393.5$ kJ/mol