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The feasible solution for a LPP is shown in Fig. Let Z = 3x – 4y be the objective function. Minimum of Z occurs atA. (0, 0)B. (0, 8)C. (5, 0)D. (4, 10) |
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Answer» B. (0, 8) Value of Z = 3x – 4y, at corner points are – At (0, 0) = 0 At (0, 8) = -32 At (4, 10) = -28 At (6, 8) = -14 At (6, 5) = -2 At (5, 0) = 15 So, clearly minimum value is at (0, 8) |
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