InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The fig shows a network consisting of an infinite number of pairs of resistors R_(1) = 2 Omega and R_(2) = 1 Omega. Since the network is infinite, removing a pair of R_(1) and R_(2) from either end of the network will not make any difference. Using this calculate the equivalent (R) across points A and B. (b) Prove that I_(n)=(I_(n-1)R_(2))/(R_(2)+R)=(I_(n-1))/(sqrt(3)+2) ltbr Where I_(n) and I_(n-1) represent the current through R_(1) in n^(th) and (n-1)^(th) segment respectively (see Fig) (c) If a 20 V battery is connected across A and B find I_(10) |
|
Answer» (C) `(20)/((sqrt(3)-1)(sqrt(3)+2)^(9))` |
|