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The figure given is made up of a square ABCD and two rhombuses ATCP and DRBV. Given that angle BVD =135° and AT=BR ,then find angle PCT and angle ABD respectively. |
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Answer» From the figure as ∠C=90° ∴∠PCT=45° ⇒∠ABD=∠ABR+∠RBD = 4 90 o
+ 4 30 o
=22.5 o +32.5 o
=55. o
HENCE, the answer is 45°,55 |
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