Saved Bookmarks
| 1. |
The figure shows a capacitor made of two circular plates each of radius 12 cm, and separated by 5.0 cm . The capacitor is beging charged by an external source (not shown in the figure. ) The charing is constant and equal to 0.15 A Obtain the displacement current across the plates. |
|
Answer» Solution :(a) `C=epsi_(0)A//d =80.1 pF` `(DQ)/(dt) =C ""(dV)/(dt)` `(dV)/(dt) =(0.15)/(80.1xx10^(-12))=1.87xx10^(9) V s^(-1)` (b) `i_(d) =epsi_(0) ""(d)/(dt) Phi _(E)`. Now across the capacitor `Phi_(E)=EA`, ignoring and CORRECTIONS. Therefore, `i_(d)=epsi_(0)A""(d Phi_(E))/(dt)` Now, `E=(Q)/(epsi_(0)A)`. Therefore, `(dE)/(dt)=(i)/(epsi_(0) A)`, which implies `i_(d)=i=0.15 A.` (c) Yes, provided by ‘CURRENT’ we mean the sum of conduction and displacement currents. |
|