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The figure shows a system of two concentric spheres of radii |
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Answer» `(r_(1)r_(2))/((r_(2)-r_(1)))` The radial rate of flow of heat through this shell in steady state will be `H=(dQ)/(dt)=-KA(dT)/(dr)=-K(4pir^(2))(dT)/(dr)` `rArrint_(r_(1))^(r_(2))(dr)/(r^(2))=-(4piK)/(H)int_(T_(1))^(T_(2))dT` This on integration and simplification gives, `H=(dQ)/(dt)=(4piKr_(1)r_(2)(T_(1)-T_(2)))/(r_(2)-r_(1))` 
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