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The figure shows tow coaxial circulalr loop a1 and 2, which forms same solid angle `theta` at point `O`. If `B_1` and `B_2` are the magnetic fields produced at the point `O` due to loop 1 and 2 respectively, then A. `B_1/B_2=1`B. `B_1/B_2=2`C. `B_1/B_2=8`D. `B_1/B_2=4` |
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Answer» Correct Answer - B `B_1 =(muIR^3)/(2(R^2+x^2)^(3/2))` `B_2=(mu_I(2R)^2)/(2[(2R)^2+(2x)^2]^(3/2))` `B_1/B_2=2` |
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