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The figureshows a modelof perfume atomizer . Whenthe bulbA is compressed , air ("density "rho_(a))flows throughthe verticaltubeand emerges throughthe end . If excesspressure appliedto the bulbins progress beDelta p thenthe minimu speed ofair in the tubeto liftperfume is : |
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Answer» ` sqrt((2 [ Delta p +o gh ])/(rho_(a)))` `P_(1) +1/2 rho_(a)v_(1)^(2) = P_(2) + 1/2 rho_(a) v_(2)^(2)` Putting` v_(1) = 0 `since of the air is at REST inside the BULB , `P_(1) = P_(10) + DeltaP_(r) P_(2) = P_(0) - rho gh ` whre `rho = ` densityof liquid( perfume) ` rho_(a)` densityof air `v_(a)`= minimumvelocityof airto lift the liquidthrough the heighth = v (say) ` P_(0)` = atmosphericpressure Hence ( A) is CORRECT
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