1.

The first diffraction minimum due to a single slite diffraction is seen at theta = 30^(@) for a light of wavelength 5000 Å falling perpendicularly on the slit. The width of the slit is:

Answer»

`5 XX 10^(-5)` cm
`2.5 xx 10^(-5)` cm
`1.25 xx 10^(-5)` cm
`10 xx 10^(-5)` cm

Solution :`Deltax = d sintheta = N lambda`
`d sin30 = 1 xx 5000 xx 10^(-10)`
`d= 10^(-6) m= 10^(-4)` cm


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