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The first excitation potential of a hypothetical hydrogen- like atom is `15 V`. Find the third excitation potential of the atom. |
Answer» Let energy of ground state `=E_(0)` `E_(0)= -13.6Z^(2)eV` and `E_(n)=(E_(0))/(n^(2))` `n=2, E_(2)=(E_(0))/(4)` given `(E_(0))/(4)-E_(0)=15` `-(3E_(0))/(4)=15` for `n=4, E_(4)=(E_(0))/(16)` third exicitation energy `=(E_(0))/(16)-E_(0)` `=-(15)/(16)E_(0)=-(15)/(16).((-4xx15)/(3))` `=(75)/(4)eV` `:.` third exclination potential is `(75)/(4)V` |
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