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The first excited state of hydrogen atom is `10.2 eV` above its ground state. The temperature is needed to excite hydrogen atoms to first excited level is |
Answer» `KE` of the hydrogen atom `3/2 kT` = `10.2 eV` = `10.2xx(1.6xx10^(-19))J` ` implies T=(2)/(3) xx (10.2xx1.6xx10^(-19))/(1.38xx10^(-23)) = 7.88xx10^(4)K` |
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