1.

The first ionisation potential of `Na` is `5.1eV`. The value of eectrons gain enthalpy of `Na^(+)` will beA. `+ 10.2 eV`B. ` –5.1 eV `C. `–10.2 eV`D. `+ 2.55 eV`

Answer» Correct Answer - B
`Moverset(M^(+))toM^++e^_ " "IE_1=5.1eV`
`M^+e^(-)toM " "DeltaH_(eg)=-5.1eV`


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