The first line in the Lyman series has wavelength `lambda`. The wavelegnth of the first line in Balmer series isA. `(2)/(9)lambda`B. `(9)/(2)lambda`C. `(5)/(27)lambda`D. `(27)/(5)lambda`

The first line in the Lyman series has wavelength `lambda`. The wavele

1.	The first line in the Lyman series has wavelength `lambda`. The wavelegnth of the first line in Balmer series isA. `(2)/(9)lambda`B. `(9)/(2)lambda`C. `(5)/(27)lambda`D. `(27)/(5)lambda`
Answer» Correct Answer - D For first line in Lyman series `lambda_(L_(1)) = (4)/(3R) ………(i)` For first line in Balmer series `lambda_(B_(1)) = (36)/(5R)……..(ii)` From equations (i) and (ii) `lambda_(B_(1))/(lambda_(L_(1))) = (27)/(5) rArr lambda_(B_(1)) = (27)/(5) lambda`

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The first line in the Lyman series has wavelength `lambda`. The wavelegnth of the first line in Balmer series isA. `(2)/(9)lambda`B. `(9)/(2)lambda`C. `(5)/(27)lambda`D. `(27)/(5)lambda`

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