The first team member in a 3person relay race must run 2 \dfrac{1}{4}2

1.	The first team member in a 3person relay race must run 2 \dfrac{1}{4}2laps, the second team member must run{1}1/2 laps, and the third team member must run 3 \dfrac{5}{8}How many laps in all must each team run?
Answer» Answer: please MARK me BRAIN list answer Step-by-step explanation: laminiaduo7 and 5 others learned from this answer You need to ADD up all 3 mixed numbers to find the total LAPS. 2 + 1/4 + 1 + 1/2 + 3 + 5/8 = (2 + 1 + 3) + (1/4 + 1/2 + 5/8) = 6 + (2/8 + 4/8 + 5/8) = 6 + (11/8) = 6 + (1 + 3/8) = 7 3/8 laps

The first team member in a 3person relay race must run 2 \dfrac{1}{4}2laps, the second team member must run{1}1/2 laps, and the third team member must run 3 \dfrac{5}{8}How many laps in all must each team run?

Answer»

Answer:

Step-by-step explanation:

laminiaduo7 and 5 others learned from this answer

You need to ADD up all 3 mixed numbers to find the total LAPS.

2 + 1/4 + 1 + 1/2 + 3 + 5/8 =

(2 + 1 + 3) + (1/4 + 1/2 + 5/8) =

6 + (2/8 + 4/8 + 5/8) =

6 + (11/8) =

6 + (1 + 3/8) =

7 3/8 laps