1.

The first term of an AP is 5 and the last term is 45. The sum is 400. Find n and d.

Answer»

Answer:

N = 16

d = 8/3

Step-by-step explanation:

SN = n/2(a+an)

400=n/2(5+45)

400=n/2*50

400x2/50 = n

n=16

Aftr this u PUT the formula...

Sn= n/2(2a+n-1)d

Hope HELPS u.........

Keep trying



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