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The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of 10 per mist 15000 find the height of the hallHint: Area of the four walls Lateral surface area)​

Answer»

loor of rectangular HALL has perimeter of 250 mCost of painting four walls at the rate of Rs 10 per m² is Rs 15000To find:Height of hall = ? Solution:Let l = lengthb = breadthh = heightPerimeter of FLOOR of a rectangular = 2502(l + B) = 250Area of four walls can be found by subtracting the area of CUBOID , area of floor and area of top surface. Area of four walls = Area of cuboid - Area of floor - Area of top surface= 2(lb + bh+ lh) - lb - lb= 2lb + 2bh + 2lh - 2lb= 2bh + 2lh= 2h(l + b) = 2h (125) = 250h m²Cost of painting 1m² is Rs 10Cost of painting 250h m² is Rs 2500hSince, we get to know that cost of painting all is Rs 1500015000 = 2500hAnswer:Thus, height of Hall is 6m



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