1.

The flux associated with surface shown in figure is......

Answer»

`(4e)/epsilon_(0)`
`(2e)/epsilon_(0)`
`e/epsilon_(0)`
0

Solution :Charge of up quark `=(2e)/3`
Charge of down quark `=-e/3`
`THEREFORE` TOTAL charge enclosed
`q=(2e)/3-e/3-e/3`
`therefore q=0`
`therefore` Flux associated, `phi=q/epsilon_(0)=0`


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