1.

The flux in a closed circuit of resistance 20ohm varies with time according to the equation phi = 6t^2-5t+1. What is the induced current at time t= 0.25 second?

Answer»

SOLUTION :`phi = 6t^2-5t+1e = -(dphi)/DT = -[12t-5] `
at time t = 0.25s, E = `-[12xx0.25-5] = 2V `
`THEREFORE i = e/R = 2/20 = 0.1A`


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