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The flux linkage in coil 1 is 3 Wb and it has 500 turns and the current in coil 2 is xA, calculate the value of x if the mutual inductance is 750H.(a) 1A(b) 2A(c) 3A(d) 4AThe question was asked during an online interview.The above asked question is from Mutual Inductance in division Inductance in a DC Circuit of Basic Electrical Engineering

Answer»

The correct option is (B) 2A

The BEST EXPLANATION: We know that mutual inductance is the PRODUCT of the number of TURNS in one coil and the flux linkages of that coil, divided by the current in the other coil.

I=3*500/750 = 2A.



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