1.

The flux linkage in coil 1 is 3Wb and it has x turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.(a) 300(b) 400(c) 500(d) 700This question was posed to me in an international level competition.My enquiry is from Mutual Inductance topic in section Inductance in a DC Circuit of Basic Electrical Engineering

Answer»

The correct option is (c) 500

Easiest EXPLANATION: We know that MUTUAL INDUCTANCE is the product of the number of turns in ONE coil and the flux LINKAGES of that coil, divided by the current in the other coil.

N=750*2/3 = 500 turns.



Discussion

No Comment Found

Related InterviewSolutions