1.

The flux linkage in coil 1 is x and it has 500 turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.(a) 1Wb(b) 2Wb(c) 3Wb(d) 4WbThe question was posed to me in semester exam.My question is from Mutual Inductance in section Inductance in a DC Circuit of Basic Electrical Engineering

Answer»

Correct CHOICE is (c) 3WB

Explanation: We KNOW that mutual inductance is the product of the NUMBER of turns in one coil and the flux linkages of that coil, divided by the CURRENT in the other coil.

φ=750*2/500 = 3Wb.



Discussion

No Comment Found

Related InterviewSolutions