1.

The flux linked with a coil at any instant 't' is given by phi=10t^2-50t+250. The induced emf at t=3s is ____

Answer»

10 V
190 V
`-190V`
`-10V`

Solution :Induced EMF `EPSILON=-(dphi)/(dt)=-d/(dt)[10t^2-50t+250]`
=-[20t-50]
Taking t=3
`THEREFORE epsilon=-[20xx3-50]`
=-[60-50]
`therefore epsilon` =-10 V


Discussion

No Comment Found

Related InterviewSolutions