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The flux of magnetic field through a closed conducting loop changes with time according to the equation phi= 0.2t^(2) + 0.4t + 0.6. Find the induced e.m.f at t= 2s. |
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Answer» SOLUTION :`phi= 0.2t^(2) + 0.4t + 0.6` `E= - (d phi)/(dt) rArr e= - 0.4t- 0.4` when `t= 2S, e= -0.8 - 0.4 = - 1.2V` |
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