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The flux of magnetic field through a closed conducting loop changes with time according to the equation phi= 0.2t^(2) + 0.4t + 0.6. Find the induced e.m.f at t= 2s.

Answer»

SOLUTION :`phi= 0.2t^(2) + 0.4t + 0.6`
`E= - (d phi)/(dt) rArr e= - 0.4t- 0.4`
when `t= 2S, e= -0.8 - 0.4 = - 1.2V`


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