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The focal chord of the parabola `y^2=a x`is `2x-y-8=0`. Then find the equation of the directrix.A. `x+4=0`B. `X-4=0`C. `Y-4=0`D. `Y++4=0` |
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Answer» Correct Answer - A The coordinates of the focus of the parabola `y^(2)=ax` are (a/4, 0). It is given that `2x-y-8=0` is a focal chord. `:." "a/2-8=0rArra=16`. The equation of the directrix is `x=-a/4" i.e. "x=-4`. |
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