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The focal chord to `y^2=16x` is tangent to `(x-6)^2+ y^2 =2` then the possible values of the slope of this chordA. (-1, 1)B. (-2, 2)C. (-2, 1/2)D. (2, -1/2) |
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Answer» Correct Answer - A The coordinates of the focus of the parabola `y^(2)=16x` are (4, 0). The equation of tangents of slope m to the circlen `(x-6)^(2)+(y-0)^(2)=(sqrt2)^(2)" are "y=m(x-6)+-sqrt2sqrt(1+m^(2))` If these tangents pass through the focus i.e. (4, 0) then `0=-2m+-sqrt2sqrt(1+m^(2))` `rArr" "4m^(2)=2(1+m)^(2)rArr2m^(2)=2rArrm=+-1` |
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