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The folllowing reading are obtained in a meter bridge experiment to find the resistivity of the material of a given wire. Calculate the resistivity of the material of the wire. Diameter of the wire =d =0.36 mm,length of the wire L = 60 cm. |
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Answer» SOLUTION :Tr 1. `R _(1)=(Sl _(1))/( 1 - l _(1)) = ( 3 xx 0. 59 )/( 0.41) = 4.32 OMEGA` Tr 2. `R _(2) = ( Sl _(2))/( 1 - l _(2)) = ( 6 xx 0. 43 )/( 0. 57 )= 4. 52 Omega ` Now : ` (##OSW_SP_PHY_XII_C03_E02_011_S01.png" width="80%"> `R _(av) = 4.42 Omega` `rho = ( PI d ^(2) R _(av ))/( 4 L )` A `rho = ( 3. 14 xx 4. 4 2xx ( 0. 36 xx 10 ^(-3)^(2)))/( 4 xx0.6)` `rho = 0. 748 xx 10 ^(-6) Omega -m` |
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