The following are the steps involved in finding the value of `(n)/(r)` from `.^(n)P_(r)=1320`. Arrange them in sequential order.A. `.^(n)P_(4)=(12!)/(9!)=(12!)/((12-3)!)`B. `rArr(n)/(r)=(12)/(3)=4`C. `rArr.^(n)P_(r)=.^(12)P_(3)`D. `.^(n)P_(r)=1320=12xx11xx10`

The following are the steps involved in finding the value of `(n)/(r)`

1.	The following are the steps involved in finding the value of `(n)/(r)` from `.^(n)P_(r)=1320`. Arrange them in sequential order.A. `.^(n)P_(4)=(12!)/(9!)=(12!)/((12-3)!)`B. `rArr(n)/(r)=(12)/(3)=4`C. `rArr.^(n)P_(r)=.^(12)P_(3)`D. `.^(n)P_(r)=1320=12xx11xx10`
Answer» DACB is the required sequential order.

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The following are the steps involved in finding the value of `(n)/(r)` from `.^(n)P_(r)=1320`. Arrange them in sequential order.A. `.^(n)P_(4)=(12!)/(9!)=(12!)/((12-3)!)`B. `rArr(n)/(r)=(12)/(3)=4`C. `rArr.^(n)P_(r)=.^(12)P_(3)`D. `.^(n)P_(r)=1320=12xx11xx10`

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