The following are the steps invovled in solving `.^(n)C_(2)=36` for n. Arrange then in sequential order.A. `n^(2)-n-72=0`B. As `sgt0,n=9`C. `n=0,n=-8`D. `(n-9)(n+8)=0`

The following are the steps invovled in solving `.^(n)C_(2)=36` for n.

1.	The following are the steps invovled in solving `.^(n)C_(2)=36` for n. Arrange then in sequential order.A. `n^(2)-n-72=0`B. As `sgt0,n=9`C. `n=0,n=-8`D. `(n-9)(n+8)=0`
Answer» EADCB is the required sequential order.

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The following are the steps invovled in solving `.^(n)C_(2)=36` for n. Arrange then in sequential order.A. `n^(2)-n-72=0`B. As `sgt0,n=9`C. `n=0,n=-8`D. `(n-9)(n+8)=0`

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