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The following concentrations wereed for the formationoand H2 at equilibrium at 500KIN21.5 x 102M. [H2]-3.0 x102 M andINH 1.2 x10 2M. Calculate equilibriumconstant. |
Answer» Equilibrium constant Kc =((1.2×10^(-2))^(2))÷((1.5×10^(-2))×(3.0×10^(-2))^(3))) =355.56 Kp=Kc(RT)^(dN)=0.211 |
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