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The following configuration of gate is equivalent to : |
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Answer» NAND `Y=(A+B).bar(AB)` The GIVEN output equation can also be written as `Y=(A+B).(bar(A)+bar(B))""` (De Morgan.s THEOREM) `=AbarA+AbarB+BbarA+BbarB=0+AbarB+barAB+0=barAB+AbarB` This is the EXPRESSION for XOR GATE. |
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