1.

The following configuration of gate is equivalent to :

Answer»

NAND
XOR
OR
NOR

Solution :Output of OR GATE =A + B
Output of NAND gate = `BAR(A.B)`
`:.` Output Y from AND gate ` = (A+B) .bar(A.B)`
`=(A+B) .(bar(A)+barB)`
`= AbarA+BbarB+AbarB+BbarA`
`=0+0+AbarB+BbarA`
`=AbarB+BbarA`
This is expression of XOR gate.


Discussion

No Comment Found

Related InterviewSolutions