1.

The following distribution gives the number of accidents met by 160 workers in a factory during a month. No. of accidents (x):01234 No. of workers (f):70523431Find the average number of accidents per worker.

Answer»

Let the assumed mean (A) = 2

 No. of accidents (xi) No. of workers (fi) ui = xi - A = xi - 2 fiui
070-2-140
152-1-52
23400
3313
4122
 N = 160\(\sum\)fiui = -187

Average number of accidents per day workers = A + \(\frac{\sum f_iu_i}{N}\)

\(=2+(-\frac{187}{160})=\frac{320-187}{160}\)

\(=0.83\) 



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