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The following measurement were taken for an unknown resistance X,with a P.O.Box, in Ohms |
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Answer» SOLUTION :The resistance X SATISFIES (i) 15`Omega` < X <16`Omega` (ii) 15.2 < X < 15.3`Omega` (iii) 15.24`Omega` < X <15.25`Omega` The error `~(1525-15 24)/(2)Omega=0.005Omega = 0.005 Omega` |
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