1.

The following table gives the number of boys of a particular age in a class of 40 students. Calculate the mean age of the students.Age (in year):151617181920No. of students:38101054

Answer»
Age (x)No. of students (y)yx
15345
168128
1710170
1810180
19595
20480
N = 40\(\sum\)yx = 698

Mean = \(\frac{\sum yx}{N}\)

\(=\frac{698}{40}=17.45\)

Therefore, 

mean age is 17.45 years.



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