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The follwing diagram indicates the energy levels of a certain atom when the system moves from `2E` level to `E`, a photon of wavelength `lambda` is emitted. The wavelength of photon produced during its transition from `(4E)/(3)` level to `E` is A. `3lambda`B. `3//4lambda`C. `lambda//4`D. `2lambda` |
Answer» Correct Answer - A `(hc)/=2E-E=Eto1,(hc)/lambda_(2)=4/3E-E=E/3to2` `lambda_(2)/lambda_(1)=(E)/(E/3)=3/1` |
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