1.

The forbiden energy gap in Ge is 0.72 eV, Given , hc=1240 eV Å . The maximum wavelength of radiation that will generate electron hole pair is :

Answer»

`172220Å`
`172.2Å`
`17222Å`
`1722Å`

SOLUTION :Energy GAP , `E_g=(HC)/lamda`
`lamda=(hc)/E_g=(12400)/(0.72)=17222Å`


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