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The force applied to a conductor is 10N if the charge in the conductor is 5C, what is the electric field intensity?(a) 10V/m(b) 2V/m(c) 3V/m(d) 15V/mI have been asked this question by my college director while I was bunking the class.My question is taken from Electric Field Strength and Electric Flux Density topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right CHOICE is (b) 2V/m

For explanation I would say: Electric FIELD intensity is the FORCE per unit charge. The formula is:

E = F/Q = 10/5 = 2V/m.



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