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The force between two charges in air is "F" the force becomes 3f/5 when placed in a medium at the same distance the electric contains of the medium is |
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Answer» Given that,The force between TWO point charges SEPARATED by a certain distance is F.Let us considered q 1 is the first CHARGE particle and q 2 is the second charge particle. r is the distance between the charge particlesq 1 and q 2 .We know that,The force isF= 4πϵ 0 1 r 2 q 1 q 2 If the charges is double and the distance between them is also doubled.Then, the force will beF’= 4πϵ 0 1 (2r) 2 2q 1 ×2q 2 F= 44F F’=FThe force will be same.Hence, this is the required solutionExplanation:hope it will help you mark me as brainliest and FOLLOW me I will follow you back |
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