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The force constant of a weightless spring is `16 N m^(-1)`. A body of mass `1.0 kg` suspended from it is pulled down through `5 cm` and then released. The maximum energy of the sysytem (spring + body) will beA. `2 xx 10^(2) J`B. `4 xx 10^(2) J`C. `8 xx 10^(2) J`D. `16 xx 10^(2) J` |
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Answer» Correct Answer - A Maximum kinetic energy = maximum elastic potential energy . `= (1)/(2) xx 16 xx ((5)/(100))^(2)J` `= (8 xx 25)/(100 xx 100) J = 2 xx 10^(2)J` |
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