The force F, and F, act on a 5kg mass. If F -20N and F = 15N and the angle betwacceleration is27een the force is 600, then them/sec2

The force F, and F, act on a 5kg mass. If F -20N and F = 15N and the a

1.	The force F, and F, act on a 5kg mass. If F -20N and F = 15N and the angle betwacceleration is27een the force is 600, then them/sec2
Answer» <p>Resultant force,F = √[(F1)^2 + (F2)^2 + 2(F1)(F2)cosθ]Assuming that F2 is horizontal in both cases, direction of F makes an angle of tanֿ¹ [F1sinθ / (F2 + F1cosθ)]</p><p>θ = 60°F = [(20)^2 + (15)^2 + 2(20)(15)cos60°] = 30.4 N=> acceleration = F/m = 30.4/5 = 6.8 m/s^2Direction of acceleration istanֿ¹ [F1sinθ / (F2 + F1cosθ)]= tanֿ¹ [20sin60° / (15 + 20cos60°)]tanֿ¹ (10√3 / 25)= 35° with F2 towards F1.</p>