The force per unit length of two conductors carrying equal currents of 5A separated by a distance of 20cm in air(in 10^-6 order)(a) 25(b) 35(c) 40(d) 50I got this question during an online exam.This intriguing question comes from Magnetic Force and Lorentz Force in division Magnetic Forces and Materials of Electromagnetic Theory

The force per unit length of two conductors carrying equal currents of

1.	The force per unit length of two conductors carrying equal currents of 5A separated by a distance of 20cm in air(in 10^-6 order)(a) 25(b) 35(c) 40(d) 50I got this question during an online exam.This intriguing question comes from Magnetic Force and Lorentz Force in division Magnetic Forces and Materials of Electromagnetic Theory
Answer» Right CHOICE is (a) 25 The best explanation: The force per unit length of TWO CONDUCTORS is GIVEN by F = μ I1xI2/2πD, where I1 = I2 = 5 and D = 0.2. Thus F = 4π x 10^-7 x 52/ 2π x 0.2 = 25 x 10^-6 units.

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