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The forcebetween two short bar magnets with magnetic moments M_(1) and M_(2)whose centres are r metre apartis 8.0 Nthen force between then is reduced to |
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Answer» Solution :`F=(mu_(0))/(4pi).(6M_(1)M_(2))/(r^(4))` `therefore F=(F)/(16)=8/16=0.5 N` |
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