1.

The forcebetween two short bar magnets with magnetic moments M_(1) and M_(2)whose centres are r metre apartis 8.0 Nthen force between then is reduced to

Answer»

4.0 n
2.0 n
1.0 n
0.5 n

Solution :`F=(mu_(0))/(4pi).(6M_(1)M_(2))/(r^(4))`
`therefore F=(F)/(16)=8/16=0.5 N`


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