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The fourth term of an Ap is 10. If eleventh term is one more three times of the fourth term find the sum of its 25 terms |
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Answer» Sum of 25 terms = 2000 t 4. =. 10 t 11. =. 3 × 10 + 1 = 31 d. = 31 - 10 / 3 = 7 t 1. = 10 - (2×7) = 10 - 14 =. -4 t 25.= t1 + 24 d = -4 + 168 =. 164 Sn. =. 25 / 2 ( -4 + 164) = (25 × 160 ) / 2. = 2000 |
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