1.

The fraction of total volume occupied by the atoms present in a simple cube is

Answer»

`(pi)/(6)`
`(pi)/(3sqrt(2))`
`(pi)/(4sqrt(2))`
`(pi)/(4)`

Solution :P.F.`=("vol. occupied by the atom in a unit CELL")/("vol. of unit cell")=((4)/(3)pir^(3))/(a^(3))`
For SIMPLE unit `a=2r=((4)/(3)pir^(3))/(8r^(3))=(4pi)/(24)=(pi)/(6)`


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